之前有朋友反馈说发的内容希望有个梯度，逐步加深，前面发了几篇关于jvm源码分析的文章，可能我觉得我已经把内容写得浅显易懂了，但是对于某些没怎么接触的同学来说还是比较难理解，这个我以后慢慢改进吧，今天发篇轻松点的文章，可能大家在工作过程中也会可能碰到类似的问题，或许有经验的同学看到这个题目就知道我要说什么了，也有自己的定位方法。
话不多说了，先来看代码吧
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| public class Test{
public static void main(String args[]){
for(int i=0;i<10;i++){
new Thread(){
public void run(){
try{
Thread.sleep(100000);
}catch(Exception e){}
}
}.start();
}
Thread t=new Thread(){
public void run(){
int i=0;
while(true){
i=(i++)/100;
}
}
};
t.setName("Busiest Thread");
t.start();
}
}
|
这个例子里新创建了11个线程，其中10个线程没干什么事，主要是sleep，另外有一个线程在循环里一直跑着，可以想象这个线程是这个进程里最耗cpu的线程了，那怎么把这个线程给抓出来呢？
首先我们可以通过top -Hp <pid>来看这个进程里所有线程的cpu消耗情况，得到类似下面的数据
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| $ top -Hp 18207
top - 19:11:43 up 573 days, 2:43, 2 users, load average: 3.03, 3.03, 3.02
Tasks: 44 total, 1 running, 43 sleeping, 0 stopped, 0 zombie
Cpu(s): 18.8%us, 0.0%sy, 0.0%ni, 81.1%id, 0.0%wa, 0.0%hi, 0.0%si, 0.0%st
Mem: 99191752k total, 98683576k used, 508176k free, 128248k buffers
Swap: 1999864k total, 191064k used, 1808800k free, 17413760k cached
PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND
18250 admin 20 0 26.1g 28m 10m R 99.9 0.0 0:19.50 java Test
18207 admin 20 0 26.1g 28m 10m S 0.0 0.0 0:00.00 java Test
18208 admin 20 0 26.1g 28m 10m S 0.0 0.0 0:00.09 java Test
18209 admin 20 0 26.1g 28m 10m S 0.0 0.0 0:00.00 java Test
18210 admin 20 0 26.1g 28m 10m S 0.0 0.0 0:00.00 java Test
18211 admin 20 0 26.1g 28m 10m S 0.0 0.0 0:00.00 java Test
18212 admin 20 0 26.1g 28m 10m S 0.0 0.0 0:00.00 java Test
18213 admin 20 0 26.1g 28m 10m S 0.0 0.0 0:00.00 java Test
18214 admin 20 0 26.1g 28m 10m S 0.0 0.0 0:00.00 java Test
18215 admin 20 0 26.1g 28m 10m S 0.0 0.0 0:00.00 java Test
18216 admin 20 0 26.1g 28m 10m S 0.0 0.0 0:00.00 java Test
18217 admin 20 0 26.1g 28m 10m S 0.0 0.0 0:00.00 java Test
18218 admin 20 0 26.1g 28m 10m S 0.0 0.0 0:00.00 java Test
18219 admin 20 0 26.1g 28m 10m S 0.0 0.0 0:00.00 java Test
18220 admin 20 0 26.1g 28m 10m S 0.0 0.0 0:00.00 java Test
18221 admin 20 0 26.1g 28m 10m S 0.0 0.0 0:00.00 java Test
18222 admin 20 0 26.1g 28m 10m S 0.0 0.0 0:00.00 java Test
18223 admin 20 0 26.1g 28m 10m S 0.0 0.0 0:00.00 java Test
18224 admin 20 0 26.1g 28m 10m S 0.0 0.0 0:00.00 java Test
18225 admin 20 0 26.1g 28m 10m S 0.0 0.0 0:00.00 java Test
18226 admin 20 0 26.1g 28m 10m S 0.0 0.0 0:00.00 java Test
18227 admin 20 0 26.1g 28m 10m S 0.0 0.0 0:00.00 java Test
|
拿到这个结果之后，我们可以看到cpu最高的线程是pid为18250的线程，占了99.9%：
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| PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND
18250 admin 20 0 26.1g 28m 10m R 99.9 0.0 0:19.50 java Test
|
接着我们可以通过jstack <pid>的输出来看各个线程栈:
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| $ jstack 18207
2016-03-30 19:12:23
Full thread dump OpenJDK 64-Bit Server VM (25.66-b60 mixed mode):
"Attach Listener" #30 daemon prio=9 os_prio=0 tid=0x00007fb90be13000 nid=0x47d7 waiting on condition [0x0000000000000000]
java.lang.Thread.State: RUNNABLE
"DestroyJavaVM" #29 prio=5 os_prio=0 tid=0x00007fb96245b800 nid=0x4720 waiting on condition [0x0000000000000000]
java.lang.Thread.State: RUNNABLE
"Busiest Thread" #28 prio=5 os_prio=0 tid=0x00007fb91498d000 nid=0x474a runnable [0x00007fb9065fe000]
java.lang.Thread.State: RUNNABLE
at Test$2.run(Test.java:18)
"Thread-9" #27 prio=5 os_prio=0 tid=0x00007fb91498c800 nid=0x4749 waiting on condition [0x00007fb906bfe000]
java.lang.Thread.State: TIMED_WAITING (sleeping)
at java.lang.Thread.sleep(Native Method)
at Test$1.run(Test.java:9)
"Thread-8" #26 prio=5 os_prio=0 tid=0x00007fb91498b800 nid=0x4748 waiting on condition [0x00007fb906ffe000]
java.lang.Thread.State: TIMED_WAITING (sleeping)
at java.lang.Thread.sleep(Native Method)
at Test$1.run(Test.java:9)
"Thread-7" #25 prio=5 os_prio=0 tid=0x00007fb91498b000 nid=0x4747 waiting on condition [0x00007fb9073fe000]
java.lang.Thread.State: TIMED_WAITING (sleeping)
at java.lang.Thread.sleep(Native Method)
at Test$1.run(Test.java:9)
"Thread-6" #24 prio=5 os_prio=0 tid=0x00007fb91498a000 nid=0x4746 waiting on condition [0x00007fb9077fe000]
java.lang.Thread.State: TIMED_WAITING (sleeping)
at java.lang.Thread.sleep(Native Method)
at Test$1.run(Test.java:9)
...
|
上面的线程栈我们注意到nid的值其实就是线程ID，它是十六进制的，我们将消耗cpu最高的线程18250，转成十六进制0x474a，然后从上面的线程栈里找到nid=0x474a的线程，其栈为：
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"Busiest Thread" #28 prio=5 os_prio=0 tid=0x00007fb91498d000 nid=0x474a runnable [0x00007fb9065fe000]
java.lang.Thread.State: RUNNABLE
at Test$2.run(Test.java:18)
|
即将最耗cpu的线程找出来了，是Businest Thread
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